Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - Chapter Review Exercises - Page 164: 69

Answer

$$ \frac{dy}{dx}=\frac{x^2}{y^2}.$$

Work Step by Step

By differentiating the equation $ x^3-y^3=4$ with respect to $ x $, we get $$3x^2-3y^2\frac{dy}{dx}=0\Longrightarrow \frac{dy}{dx}=\frac{x^2}{y^2}.$$
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