Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - Chapter Review Exercises - Page 164: 71



Work Step by Step

By differentiating the equation $ y=xy^2+2x^2$ with respect to $ x $, we get $$\frac{dy}{dx}=y^2+2xy \frac{dy}{dx}+4x\Longrightarrow \frac{dy}{dx}(1-2xy)=y^2+4x $$ and hence $$\frac{dy}{dx}=\frac{y^2+4x}{1-2xy}.$$
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