#### Answer

$432000\pi\, cm^{3}/min $

#### Work Step by Step

$\frac{dV}{dt}=\frac{dV}{dr}\times\frac{dr}{dt}=\frac{d}{dr}(\frac{4}{3}\pi r^{3})\times30\,cm/min $
$=4\pi r^{2}\times30\,cm/min $
As $\frac{dr}{dt}=30\,cm/min $ and $ r=0$ at $ t=0$, the radius at t=2 min is $2\,min\times30\,cm/min=60\,cm $
Then, $\frac{dV}{dt}|_{t=2\,min}=4\pi(60\,cm)^{2}\times30\,cm/min=432000\pi\, cm^{3}/min $