#### Answer

$14.4\,ft^{3}/min $

#### Work Step by Step

$\frac{dV}{dh}=\frac{d}{dh}(18\,ft^{2}\times h)=18\,ft^{2}$
$\frac{dh}{dt}=0.8\,ft/min $
$\frac{dV}{dt}=\frac{dV}{dh}\times \frac{dh}{dt}=18\,ft^{2}\times0.8\,ft/min $
$=14.4\,ft^{3}/min $

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Published by
W. H. Freeman

ISBN 10:
1464125260

ISBN 13:
978-1-46412-526-3

$14.4\,ft^{3}/min $

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