Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - 3.9 Related Rates - Exercises - Page 159: 1


0.039 ft/min

Work Step by Step

Volume V= Base area $\times $ Height $=18\,ft^{2}\times h $ $\frac{dV}{dh}=\frac{d}{dh}(18\,ft^{2}\times h)= 18\,ft^{2}$ $\frac{dV}{dt}=0.7 ft^{3}/min $ $\frac{dh}{dt}=\frac{\frac{dV}{dt}}{\frac{dV}{dh}}=\frac{0.7\,ft^{3}/min}{18\,ft^{2}}= 0.039\,ft/min $
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