Answer
$y' = -\frac{2x}{9y^2}$
Work Step by Step
$\frac{d}{dx}(3y^3) + \frac{d}{dx}(x^2) = \frac{d}{dx}(5)$
$3*3y^2(y') + 2x = 0$
$9y^2(y') + 2x = 0$
Now we have to solve for $y'$:
$9y^2(y') = -2x$
$y' = -\frac{2x}{9y^2}$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - 3.8 Implicit Differentiation - Exercises - Page 152: 9
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