## Calculus (3rd Edition)

$\frac{3x^{2}-y^{2}-2xy^{5}}{2xy+x^{2}5y^{4}}$
Differentiating with respect to $x$, we have $1\times y^{2}+2yy'\times x+2xy^{5}+x^{2}5y^{4}y'-3x^{2}=0$ $\implies 2xyy'+x^{2}5y^{4}y'=3x^{2}-y^{2}-2xy^{5}$ $\implies y'=\frac{3x^{2}-y^{2}-2xy^{5}}{2xy+x^{2}5y^{4}}$