Answer
$$\frac{d}{dx}\tan(xy)= (y+x\frac{dy}{dx})\sec^2 (xy).$$
Work Step by Step
Recall the product rule: $(uv)'=u'v+uv'$
Recall that $(\tan x)'=\sec^2 x$.
Using the chain rule, we have
$$\frac{d}{dx}\tan(xy)= (y+x\frac{dy}{dx})\sec^2 (xy).$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - 3.8 Implicit Differentiation - Exercises - Page 152: 6
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
