Answer
$$0$$
Work Step by Step
We evaluate the limit:
\begin{align*}
\lim _{x \rightarrow \infty}\left(\frac{1}{x}-\frac{1}{x+2}\right)&=\lim _{x \rightarrow \infty} \frac{1}{x}-\lim _{x \rightarrow \infty} \frac{1}{x+2}\\
&=0
\end{align*}
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 2 - Limits - 2.7 Limits at Infinity - Exercises - Page 83: 38
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