Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - 2.7 Limits at Infinity - Exercises - Page 83: 25



Work Step by Step

We have \begin{align*} \lim _{x \rightarrow- \infty}\frac{8x^2+7x^{1/3}}{\sqrt{16x^4+6}} &= \lim _{x \rightarrow- \infty}\frac{8+\frac{7}{x^{5/3}}}{\sqrt{16+\frac{6}{x^4}}} \\ &=\frac{8+0}{\sqrt{16+0}} \\ &=\frac{8}{4}=2. \end{align*}
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