## Calculus (3rd Edition)

Published by W. H. Freeman

# Chapter 2 - Limits - 2.7 Limits at Infinity - Exercises - Page 83: 30

#### Answer

$\frac{4}{5}$

#### Work Step by Step

We have $$\lim _{t \rightarrow-\infty} \frac{4+5^{2 t}}{5-5^{3 t}}= \frac{4+5^{-\infty}}{5-5^{-\infty}}=\frac{4+0}{5-0}=\frac{4}{5}$$.

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