## Calculus (3rd Edition)

Published by W. H. Freeman

# Chapter 16 - Multiple Integration - 16.1 Integration in Two Variables - Exercises - Page 846: 10

#### Answer

$-45$

#### Work Step by Step

Using the formula $$\iint_{\mathcal{R}} C d A=C \cdot \operatorname{Area}(\mathcal{R})$$ We have $$\iint_{\mathcal{R}} -5 d A=(-5)(5-2)(7-4)=-5(3)(3)=-45.$$

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