#### Answer

See the explanation below.

#### Work Step by Step

The projection onto the xy-plane is traced by $\langle \sin t,0\rangle $ which is a segment $[-1,1] $ on the x-axis since $-1\leq \sin t \leq 1$.
The projection onto the xz-plane is the circle itself. We put $$ x=\sin t, z-4=\cos t $$
hence we get $$ x^2+(z-4)^2=1$$
which is a circle of radius $1$ centered at $(0,0,4)$.
The projection onto the yz-plane is traced by $\langle 0,0,4+\cos t\rangle $ which is a segment $[3,5] $ on the z-axis since $3=4-1\leq 4+ \cos t \leq 4+1=5$.