Answer
Circle in the vertical plane $(y=9)$ of raduis $3 $ centered at $(6,9,4)$.
Work Step by Step
We put
$$ x=6+3\sin t,\quad y=9, \quad z=4+3\cos t $$
hence we get
$$(x-6)^2+(z-4)^2=9\sin^2t+9\cos^2t=9.$$
Which is a circle in the vertical plane $(y=9)$ of raduis $3 $ centered at $(6,9,4)$.
