## Calculus (3rd Edition)

$(2,0,\frac{\pi}{3})$.
Since $x=\sqrt3, \, y=0, \, z=1$ and $$\rho=\sqrt{x^2+y^2+z^2},\quad \theta=\tan^{-1}( y/x), \quad \phi=\cos^{-1}(z/\rho),$$ then we have $$\rho=\sqrt{\sqrt 3^2+0+1^2}=\sqrt{4}=2,$$ $$\theta=\tan^{-1}( 0)=0,$$ $$\phi=\cos^{-1}(1/2)=\frac{\pi}{3}$$ Hence, the spherical coordinates are $(2,0,\frac{\pi}{3})$.