## Calculus (3rd Edition)

Published by W. H. Freeman

# Chapter 13 - Vector Geometry - 13.3 Dot Product and the Angle Between Two Vectors - Exercises - Page 666: 6

#### Answer

$\frac{3}{4}$

#### Work Step by Step

Recall that $\cdot= a_{1}a_{2}+b_{1}b_{2}$ Then, $\cdot<3,\frac{1}{2}>=\frac{1}{6}\times3+\frac{1}{2}\times\frac{1}{2}= \frac{3}{4}$

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