Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.3 Dot Product and the Angle Between Two Vectors - Exercises - Page 666: 41


$$2u\cdot(3u- v) =2.$$

Work Step by Step

We have $$2u\cdot(3u- v)=6u\cdot u-2u\cdot v=6\| u\|^2-2u\cdot v\\ =6(1^2)-2(2)=6-4=2.$$
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