Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.3 Dot Product and the Angle Between Two Vectors - Exercises - Page 666: 7

Answer

0

Work Step by Step

$\textbf{k}\cdot\textbf{j}=kj \cos \theta= 1\times1\times\cos 90^{\circ}= 0$
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