Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - Chapter Review Exercises - Page 638: 11


$$y= \frac{8}{(3-x)^3}+\frac{3-x}{2}.$$

Work Step by Step

We set $x=3-2/t$. Solve for $t$ to get: $t= \frac{2}{3-x}$ Now plug into the $y$ equation: $$y= t^3+1/t=\frac{8}{(3-x)^3}+\frac{3-x}{2}.$$
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