Answer
$$y= \frac{8}{(3-x)^3}+\frac{3-x}{2}.$$
Work Step by Step
We set $x=3-2/t$. Solve for $t$ to get:
$t= \frac{2}{3-x}$
Now plug into the $y$ equation:
$$y= t^3+1/t=\frac{8}{(3-x)^3}+\frac{3-x}{2}.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - Chapter Review Exercises - Page 638: 11
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