## Calculus (3rd Edition)

$R-\{0,1\}$.
Since $x^{-4}=\frac{1}{x^4}$, then $x\neq 0$. Also, $(x-1)^{-3}=\frac{1}{(x-1)^3}$, so $x\neq 1$. Hence, the domain of $f$ is $R-\{0,1\}$.