Calculus (3rd Edition)

Published by W. H. Freeman

Chapter 1 - Precalculus Review - 1.3 The Basic Classes of Functions - Exercises - Page 22: 10

Answer

$R-\{-1\}$

Work Step by Step

Since $s+1=0\Longrightarrow s=-1$, hence $\frac{s}{s+1}$ is not defined when $s=-1$. Thus the domain of $F$ is $R-\{-1\}$.

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