$$ x=0, x=\pm 2.$$
Work Step by Step
The zeros of $f(x)= x^3-4x$ can be obtained by putting $$x^3-4x=0\Longrightarrow x(x^2-4)=0 \Longrightarrow x=0, x=\pm 2.$$ Since $f(-x)=-f(x)$.
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