Answer
$$ x=0, x=\pm 2.$$
Work Step by Step
The zeros of $f(x)= x^3-4x$ can be obtained by putting
$$x^3-4x=0\Longrightarrow x(x^2-4)=0 \Longrightarrow x=0, x=\pm 2.$$
Since $f(-x)=-f(x)$.
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 1 - Precalculus Review - 1.1 Real Numbers, Functions, and Graphs - Exercises - Page 10: 55
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