# Chapter 1 - Precalculus Review - 1.1 Real Numbers, Functions, and Graphs - Exercises - Page 10: 53

the zeros are $$x=\pm 2.$$

#### Work Step by Step

The zeros of $f(x)=x^2-4$ can be obtained by putting $$x^2-4=0\Longrightarrow x=\pm 2.$$ Since $f(-x)=f(x)$ then the function is symmetric about the y-axis and increasing on the interval $(0,\infty)$ as in the figure below.

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