## Calculus (3rd Edition)

Published by W. H. Freeman

# Chapter 1 - Precalculus Review - 1.1 Real Numbers, Functions, and Graphs - Exercises - Page 10: 36

#### Answer

1) d = $2\sqrt 2$ 2) d = $3$ 3) d = $\sqrt {13}$ 4) d = $\sqrt {37}$

#### Work Step by Step

The distance between point (x_{1}, y_{1}) and the point (x_{2}, y_{2}) is: $d = \sqrt {(x_2-x_1)^{2}+(y_2-y_1)^{2}}$ 1) Points (1,4) and (3,2): $d = \sqrt {(3-1)^{2}+(2-4)^{2}}$ $d= 2\sqrt2$ 2) Points (2,4) and (2,1): $d = \sqrt {(2-2)^{2}+(1-4)^{2}}$ $d= 3$ 3) Points (-2,3) and (0,0): $d = \sqrt {(0-(-2))^{2}+(0-3)^{2}}$ $d= \sqrt{13}$ 4) Points (-2,3) and (-3,-3): $d = \sqrt {(-3-(-2))^{2}+(-3-3)^{2}}$ $d= \sqrt{37}$

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