Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Infinite Series - Review Exercises - Page 677: 40

Answer

Converges to $\dfrac{2}{3}$

Work Step by Step

We are given the sequence $a_n=\dfrac{2n+1}{3n+2}$ We will apply the nth test to check whether the given series converges or diverges. So, we have $\lim\limits_{n \to \infty} \dfrac{2n+1}{3n+2}=\lim\limits_{n \to \infty} \dfrac{2+1/n}{3+2/n}=\dfrac{2+0}{3+0}=\dfrac{2}{3}$ This means that the given sequence converges to $\dfrac{2}{3}$.
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