Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Infinite Series - 9.5 Exercises - Page 625: 7

Answer

Converges by Alternating Series Test

Work Step by Step

Rewrite Summation, $\Sigma^{\infty}_{n=1} (-1)^n \frac{1}{3^n}$ Test for two conditions of Alternating Series i.) $\lim\limits_{n \to \infty} \frac{1}{3^n} =0$ ii.) $a_{n+1} = \frac{1}{3^{n+1}} \leq \frac{1}{3^n} = a_n$ Both condition are satisfied so the Series converges by the Alternating Series Test
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