Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Infinite Series - 9.5 Exercises - Page 625: 20

Answer

Series Converges by Theorem 9.14

Work Step by Step

Rewrite Summation to identify $a_n$, $\Sigma^{\infty} _{n=0} (-1)^n \frac{1}{(2n+1)!} $ Apply alternating Series Test i.) $\lim\limits_{n \to \infty} \frac{1}{(2n+1)!} = 0 $ ii.) $ a_{n+1} = \frac{1}{(2n+3)!} \leq \frac{1}{(2n+1)!}= a_n$ The Sum satisfies the conditions and Converges by Theorem 9.14
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