Answer
Diverges by n-th term test
Work Step by Step
$\Sigma^{\infty} _{n+1} (-1)^n \frac{5n-1}{4n+1}$
Apply n-th term test
$\lim\limits_{n \to \infty} \frac{5n-1}{4n+1} = \frac{5}{4} \ne 0 $
Limit diverges by n-th term test
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