Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Infinite Series - 9.4 Exercises - Page 618: 61

Answer

Converges

Work Step by Step

We will apply the limit comparison test with $a_n=\Sigma_{n=1}^{\infty} \dfrac{1}{(n+1)^3}$ and $b_n=\Sigma_{n=1}^{\infty} \dfrac{1}{n^2}$ We can see that the series $\Sigma b_n$ shows a convergent p-series with $p=2 \gt 1$. Next, we have $\lim\limits_{n \to \infty} \dfrac{a_n}{b_n} =\lim\limits_{n \to \infty} [\dfrac{\dfrac{1}{(n+1)^3}}{1/n^2}]$ or, $=\lim\limits_{n \to \infty} \dfrac{1/n }{(1+1/n)^3}$ or, $=0$ Hence, we can see that the given series converges by the limit comparison test.
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