Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Infinite Series - 9.1 Exercises - Page 593: 60

Answer

Not monotonic, Bounded

Work Step by Step

Let's calculate the value of initial terms of the sequence to get an insight. $a_1=\:\frac{cos\left(1\right)}{1}\:=\:0.54$ $a_2=\:\frac{cos\left(2\right)}{2}\:=\:-0.208$ $a_2=\:\frac{cos\left(3\right)}{3}\:=\:-0.33$ $a_4=\:\frac{cos\left(4\right)}{4}\:=\:-0.163$ Thus, the sequence is not monotonic as the terms decrease till the third term when they start rising and it keeps changing as can be seen by the graph. Hence, the sequence is not monotonic. We know that cos(x) is bounded from above and below by 1 and -1 respectively, and dividing it by any positive numbers only makes it go nearer to 0. So $\frac{cos(n)}{n}$ is bounded.
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