Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Infinite Series - 9.1 Exercises - Page 593: 56

Answer

Not monotonic, but bounded

Work Step by Step

Because the sequence isn’t always decreasing or increasing, it’s not monotonic. To find if it is bounded. Find $\lim\limits_{n \to \infty} n e^{-\frac{n}{2}}$ From both intuition and the graph of the function it is clear that $ \frac{2}{e} \geq a_n \geq 0$. Because the maximum of $\frac{2}{e}$ is the upper bound and 0 is the lower bound as n goes to $\infty$
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