Answer
$5+ce^{-x^{2}}$
Work Step by Step
Solve by integrating factor, I(x)
I(x) = $e^{\int2xdx}$
= $e^{x^{2}}$
$$e^{x^{2}}y= \int e^{x^{2}}10xdx$$
$$e^{x^{2}}y= 5\int e^{x^{2}}2xdx$$
$$e^{x^{2}}y= 5e^{x^{2}}+c$$
$$y= 5+ce^{-x^{2}}$$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 6 - Differential Equations - 6.4 Exercises - Page 428: 8
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