Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 6 - Differential Equations - 6.4 Exercises - Page 428: 5



Work Step by Step

$\frac{dy}{dx}+(\frac{1}{x})y=6x+2$ Integrating factor: $e^{\int(\frac{1}{x})dx}$ $e^{\int(\frac{1}{x})dx}=e^{lnx}=x$ $xy=\int$x(6x+2)dx $\int$x(6x+2)dx=2$x^{3}+x^{2}+C$ $y=2x^{2}+x+\frac{C}{x}$
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