Answer
$y=2x^{2}+x+\frac{C}{x}$
Work Step by Step
$\frac{dy}{dx}+(\frac{1}{x})y=6x+2$
Integrating factor: $e^{\int(\frac{1}{x})dx}$
$e^{\int(\frac{1}{x})dx}=e^{lnx}=x$
$xy=\int$x(6x+2)dx
$\int$x(6x+2)dx=2$x^{3}+x^{2}+C$
$y=2x^{2}+x+\frac{C}{x}$