Answer
$y=(x+C)e^{x^{3}}$
Work Step by Step
$y'-3x^{2}y=e^{x^{3}}$
Integrating factor: $e^{-\int 3e^{x^{2}}dx}=e^{-x^{3}}$
$ye^{-x^{3}}$=$\int$$e^{x^{3}}e^{-x^{3}}dx$=$\int$dx=$x+C$
$y=(x+C)e^{x^{3}}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 6 - Differential Equations - 6.4 Exercises - Page 428: 13
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