## Calculus 10th Edition

Published by Brooks Cole

# Chapter 6 - Differential Equations - 6.4 Exercises - Page 428: 13

#### Answer

$y=(x+C)e^{x^{3}}$

#### Work Step by Step

$y'-3x^{2}y=e^{x^{3}}$ Integrating factor: $e^{-\int 3e^{x^{2}}dx}=e^{-x^{3}}$ $ye^{-x^{3}}$=$\int$$e^{x^{3}}e^{-x^{3}}dx$=$\int$dx=$x+C$ $y=(x+C)e^{x^{3}}$

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