Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.7 Exercises - Page 382: 74

$${\text{FALSE}}$$

$$\eqalign{ & \int {\frac{{2{e^{2x}}}}{{\sqrt {9 - {e^{2x}}} }}dx} \cr & {\text{Let }}u = {e^x}{\text{, }}du = {e^x}dx{\text{ and }}a = 3 \cr & \int {\frac{{2{e^{2x}}}}{{\sqrt {9 - {e^{2x}}} }}dx} = \int {\frac{{2u}}{{\sqrt {{a^2} - {u^2}} }}du} \cr & {\text{False, it is not possible to use the arcsine rule}} \cr} $$