Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.7 Exercises - Page 382: 73

$${\text{TRUE}}$$

$$\eqalign{ & \int {\frac{{dx}}{{\sqrt {4 - {x^2}} }}} \cr & {\text{Rewrite the integrand}} \cr & = \int {\frac{{dx}}{{\sqrt {{2^2} - {x^2}} }}} \cr & {\text{Integate by the formula }}\int {\frac{{du}}{{{a^2} + {x^2}}}} = - \arccos \left( {\frac{x}{a}} \right) + C \cr & \int {\frac{{dx}}{{\sqrt {{2^2} - {x^2}} }}} = - \arccos \left( {\frac{x}{2}} \right) + C \cr & {\text{Therefore, the statement is TRUE}} \cr} $$