Answer
$\frac{32}{3ln(3)}$
Work Step by Step
solve for indefinite integral
let u=$\frac{x}{4}$
$\frac{1}{4}dx=du$
$dx=4du$
$\int3^{\frac{x}{4}}dx$
$=\int 3^udu$
$=\frac{3^u}{ln(3)}+C$
$=\frac{3^{\frac{x}{4}}}{ln(3)}+C$
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$\int3^{\frac{x}{4}}dx$ [-4,4]
$=\frac{3^{-1}}{ln(3)}-\frac{3}{ln(3)}$
$=\frac{32}{3ln(3)}$
