Calculus 10th Edition

$\frac{32}{3ln(3)}$
solve for indefinite integral let u=$\frac{x}{4}$ $\frac{1}{4}dx=du$ $dx=4du$ $\int3^{\frac{x}{4}}dx$ $=\int 3^udu$ $=\frac{3^u}{ln(3)}+C$ $=\frac{3^{\frac{x}{4}}}{ln(3)}+C$ ---- $\int3^{\frac{x}{4}}dx$ [-4,4] $=\frac{3^{-1}}{ln(3)}-\frac{3}{ln(3)}$ $=\frac{32}{3ln(3)}$