Answer
$\frac{7}{2\log2}$
Work Step by Step
Note that $\log$ denotes the natural logarithm.
$\int 2^x dx $
$= \frac{2^x}{\log 2}+C$ (indefinite integral)
$=(\frac{2^2}{\log2})-(\frac{2^{-1}}{\log2})$ $[-1,2]$
$=\frac{4}{\log 2}{-\frac{1}{2 \log2}}$
$=\frac{7}{2\log2}$
