Answer
$\frac{2^{sin(x)}}{ln(2)}+C$
Work Step by Step
let u=$sin(x)$
$cos(x)dx=du$
$dx=\frac{1}{cos(x)}du$
$\int2^{sin(x)}cos(x)dx$
$=\int 2^udu$
$=\frac{2^u}{ln(2)}+C$
$=\frac{2^{sin(x)}}{ln(2)}+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises - Page 363: 78
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