Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises: 78

Answer

$\frac{2^{sin(x)}}{ln(2)}+C$

Work Step by Step

let u=$sin(x)$ $cos(x)dx=du$ $dx=\frac{1}{cos(x)}du$ $\int2^{sin(x)}cos(x)dx$ $=\int 2^udu$ $=\frac{2^u}{ln(2)}+C$ $=\frac{2^{sin(x)}}{ln(2)}+C$
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