## Calculus 10th Edition

$\frac{2^{sin(x)}}{ln(2)}+C$
let u=$sin(x)$ $cos(x)dx=du$ $dx=\frac{1}{cos(x)}du$ $\int2^{sin(x)}cos(x)dx$ $=\int 2^udu$ $=\frac{2^u}{ln(2)}+C$ $=\frac{2^{sin(x)}}{ln(2)}+C$