Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.2 Exercises - Page 263: 6

Answer

238

Work Step by Step

$\displaystyle \sum_{i=1}^{4}[(i-1)^{2}+(i+1)^{3}]=$S There are four terms in the sum : $i=1:\qquad (0+8)=8$ $i=2:\qquad (1+27)=28$ $i=3:\qquad (4+64)=68$ $i=4:\qquad (9+125)=134$ S$=8+28+68+134=238$
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