## Calculus 10th Edition

$\displaystyle \sum_{i=1}^{4}[(i-1)^{2}+(i+1)^{3}]=$S There are four terms in the sum : $i=1:\qquad (0+8)=8$ $i=2:\qquad (1+27)=28$ $i=3:\qquad (4+64)=68$ $i=4:\qquad (9+125)=134$ S$=8+28+68+134=238$