Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.2 Exercises - Page 263: 8

Answer

$$\sum_{n=1}^{14}\frac{9}{1+n}$$

Work Step by Step

$\frac{9}{1+1}+\frac{9}{1+2}+\frac{9}{1+3}+..+\frac{9}{1+14}$ $$=\sum_{n=1}^{14}\frac{9}{1+n}$$
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