Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.2 Exercises - Page 263: 7

Answer

$$\sum_{n=1}^{11}\frac{1}{5n}$$

Work Step by Step

$\frac{1}{5(1)}+\frac{1}{5(2)}+\frac{1}{5(3)}+...+\frac{1}{5(11)}$ The denominator simply goes up by 5 and therefore $$\frac{1}{5(1)}+\frac{1}{5(2)}+\frac{1}{5(3)}+...+\frac{1}{5(11)}=\sum_{n=1}^{11}\frac{1}{5n}$$
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