Answer
The absolute maximum is $4$ at $x=-2$,
The absolute minimum is $0$ when $x\in(1,2]$
Work Step by Step
Graphing the function (see below),
h(x) = the greatest integer $n$ such that $ n\leq (2-x).$
$h(-2)=4$, because $4\leq 2+2$
$h(-1.5)=3$, because $3\leq 2+1.5$
$h(-1)=3$, because $3\leq 2+1$
$...$
$h(1)=1$ because $1\leq 2-1$
$h(1.1)=0$ because $0\leq 2-1.1$
$h(2)=0$ because $0\leq 2-21$
The absolute maximum is $4$ at $x=-2$,
The absolute minimum is $0$ when $x\in(1,2]$
