## Calculus 10th Edition

The function has an absolute maximum equal to $5$ and an absolute minimum equal to $-4$ over the specified interval.
$h'(x)=-2x.$ $h'(x)$ is defined for all x in the interval. $h'(x)=0\to x=0;$ hence, $x=0$ is, along with the endpoints of the interval, a possible candidate for an absolute extrema. $h(-3)=-4.$ $h(0)=5.$ $h(1)=4.$ The function has an absolute maximum equal to $5$ and an absolute minimum equal to $-4$ over the specified interval.