Answer
$g'(2)=0.$
Work Step by Step
$g'(x)=1-\dfrac{8}{x^3}.$
$g'(2)=1-\dfrac{8}{2^3}=0.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 3 - Applications of Differentiation - 3.1 Exercises - Page 167: 3
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
