Answer
a) 12 ft/sec
b) 6 ft/sec
c) 3 ft/sec
Work Step by Step
y = tanx
$\frac{dy}{dt} = sec^2(x) \frac{dx}{dt} $
dx/dt = 3 ft/sec
a) x = -$\frac{\pi}{3} $
$\frac{dy}{dt} = sec^2(-\frac{\pi}{3} )(3) = 12$
b) x = -$\frac{\pi}{4} $
$\frac{dy}{dt} = sec^2(-\frac{\pi}{4} )(3) = 6$
c) x = 0
$\frac{dy}{dt} = sec^2(0 )(3) = 3$