Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.6 Exercises - Page 153: 11


a) $64 \pi cm^2/sec$ b) $256 \pi cm^2/sec$

Work Step by Step

The area of a circle is given by $A = \pi r^2$ If the radius is increasing at 4 cm/min, this means $\frac{dr}{dt} = 4$ To find the rate of change of the area, we have $\frac{dA}{dt} = 2\pi r \frac{dr}{dt} $ a) when r = 8cm we have $\frac{dA}{dt} = 2\pi (8)(4) = 64\pi cm^2/sec $ b) when r = 32cm we have $\frac{dA}{dt} = 2\pi (32)(4) = 256\pi cm^2/sec $
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