Answer
$h'(x)=\dfrac{x\cos{x}}{|x|}-|x|\sin{x}$
Work Step by Step
Product Rule: $(h’(x)=(u(x)(v(x))’=u’(x)v(x)+u(x)v’(x))$
$u(x)=|x| ;u’(x)=\dfrac{x}{|x|} $
$v(x)=\cos{x} ;v’(x)= -\sin{x}$
$h'(x)=\dfrac{x\cos{x}}{|x|}-|x|\sin{x}$ ; $x\ne0.$
