Answer
$f'(x)=\dfrac{2x^3-18x}{|x^2-9|}.$
Work Step by Step
$u=x^2-9$; $u'=2x$
$f'(x)=u'\dfrac{u}{|u|}=\dfrac{2x^3-18x}{|x^2-9|}.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - 2.4 Exercises - Page 139: 120
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