Answer
False.
Work Step by Step
Correct solution:
$u=\sin{2x}$; $\dfrac{du}{dx}=2\cos{2x}$
$\dfrac{d}{du}f(u)=2u$
$\dfrac{d}{dx}f(x)=\dfrac{d}{du}f(u)\times\dfrac{du}{dx}=4\cos{2x}\sin{2x}.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - 2.4 Exercises - Page 139: 126
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